How To Find Directrix Of Ellipse

Kalali
Jun 13, 2025 · 3 min read

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How to Find the Directrix of an Ellipse
Finding the directrix of an ellipse might seem daunting, but with a clear understanding of the ellipse's properties and a systematic approach, it becomes manageable. This article will guide you through the process, explaining the concepts and providing you with the formulas you need. Understanding the directrix is crucial for grasping the fundamental nature of conic sections and their geometric properties.
Understanding the Ellipse and its Directrix
An ellipse is defined as the set of all points in a plane such that the sum of the distances from each point to two fixed points (the foci) is constant. The directrix, on the other hand, is a straight line associated with each focus. The ratio of the distance from a point on the ellipse to a focus and the distance from that same point to the corresponding directrix is a constant value, known as the eccentricity (e). This eccentricity is always less than 1 for an ellipse.
Formulas for Finding the Directrix
The location of the directrix depends on the orientation of the ellipse (horizontal or vertical major axis) and the values of its semi-major axis (a) and eccentricity (e).
1. Ellipse with a Horizontal Major Axis:
The standard equation for an ellipse with a horizontal major axis centered at (h, k) is:
(x-h)²/a² + (y-k)²/b² = 1
where:
- a is the length of the semi-major axis.
- b is the length of the semi-minor axis.
- (h,k) is the center of the ellipse.
The eccentricity (e) is calculated as: e = √(a² - b²)/a
The directrices are vertical lines located at:
x = h ± a/e
This gives you two directrices, one on each side of the ellipse.
2. Ellipse with a Vertical Major Axis:
The standard equation for an ellipse with a vertical major axis centered at (h, k) is:
(x-h)²/b² + (y-k)²/a² = 1
Notice that 'a' and 'b' have switched places compared to the horizontal case. The eccentricity remains calculated as: e = √(a² - b²)/a
The directrices are horizontal lines located at:
y = k ± a/e
Again, this provides two directrices, symmetrically positioned relative to the ellipse.
Step-by-Step Example: Finding the Directrix of a Horizontal Ellipse
Let's say we have an ellipse with the equation: (x-2)²/9 + (y+1)²/4 = 1
-
Identify the values: Here, a² = 9, so a = 3; b² = 4, so b = 2; h = 2; k = -1.
-
Calculate the eccentricity (e):
e = √(9 - 4)/3 = √5/3
-
Find the directrices: Using the formula
x = h ± a/e
, we get:x = 2 ± 3/(√5/3) = 2 ± 9/√5
Therefore, the two directrices are approximately
x ≈ 2 + 4.02 ≈ 6.02
andx ≈ 2 - 4.02 ≈ -2.02
.
Conclusion:
Finding the directrices of an ellipse involves understanding its equation, calculating the eccentricity, and applying the appropriate formula based on the ellipse's orientation. By following these steps and understanding the underlying concepts, you can confidently determine the location of the directrices for any given ellipse. Remember to always double-check your calculations to ensure accuracy. Mastering this skill enhances your comprehension of elliptical geometry and its applications in various fields.
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