What Is The Solution Set Of The Quadratic Inequality

Kalali
Mar 25, 2025 · 6 min read

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What is the Solution Set of a Quadratic Inequality? A Comprehensive Guide
Solving quadratic inequalities might seem daunting at first, but with a structured approach and understanding of the underlying concepts, you can master this essential skill in algebra. This comprehensive guide will walk you through the process step-by-step, providing clear explanations, examples, and tips to help you confidently solve any quadratic inequality.
Understanding Quadratic Inequalities
A quadratic inequality is an inequality that involves a quadratic expression. A quadratic expression is an expression of the form ax² + bx + c, where 'a', 'b', and 'c' are constants, and 'a' is not equal to zero. The inequality can be one of four types:
- ax² + bx + c > 0
- ax² + bx + c < 0
- ax² + bx + c ≥ 0
- ax² + bx + c ≤ 0
The solution set of a quadratic inequality is the set of all real numbers that satisfy the inequality. Unlike quadratic equations which often have only one or two solutions, quadratic inequalities typically have an infinite number of solutions represented by intervals on the number line.
Steps to Solve a Quadratic Inequality
Solving a quadratic inequality involves several key steps:
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Rewrite the Inequality: Ensure the inequality is in the standard form: ax² + bx + c > 0 (or <, ≥, ≤ 0). If it's not, rearrange the terms to achieve this form.
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Find the Roots (x-intercepts): Solve the corresponding quadratic equation ax² + bx + c = 0. This can be done using various methods such as factoring, the quadratic formula, or completing the square. These roots represent the points where the parabola intersects the x-axis.
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Sketch the Parabola: Determine whether the parabola opens upwards (a > 0) or downwards (a < 0). This is crucial for understanding the inequality's solution. A positive 'a' indicates a parabola opening upwards (U-shape), while a negative 'a' indicates a downward-opening parabola (inverted U-shape). Plot the roots (x-intercepts) on a number line.
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Test Intervals: The roots divide the number line into intervals. Choose a test point from each interval and substitute it into the original inequality. If the test point satisfies the inequality, then all points in that interval are part of the solution set.
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Write the Solution Set: Based on the test results, express the solution set using interval notation or set-builder notation. Remember to consider whether the inequality includes or excludes the roots (i.e., > vs. ≥, or < vs. ≤).
Examples: Solving Quadratic Inequalities
Let's illustrate the process with several examples:
Example 1: x² - 4x + 3 > 0
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Standard Form: The inequality is already in standard form.
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Find the Roots: Factor the quadratic: (x - 1)(x - 3) = 0. The roots are x = 1 and x = 3.
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Sketch the Parabola: Since a = 1 > 0, the parabola opens upwards.
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Test Intervals:
- Interval 1: x < 1: Let's test x = 0: (0)² - 4(0) + 3 = 3 > 0. This interval is part of the solution.
- Interval 2: 1 < x < 3: Let's test x = 2: (2)² - 4(2) + 3 = -1 > 0 (False). This interval is NOT part of the solution.
- Interval 3: x > 3: Let's test x = 4: (4)² - 4(4) + 3 = 3 > 0. This interval is part of the solution.
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Solution Set: The solution set is (-∞, 1) ∪ (3, ∞). This means all x-values less than 1 or greater than 3 satisfy the inequality.
Example 2: -x² + 2x + 8 ≤ 0
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Standard Form: The inequality is in standard form.
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Find the Roots: We can factor this as -(x - 4)(x + 2) = 0. The roots are x = 4 and x = -2.
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Sketch the Parabola: Since a = -1 < 0, the parabola opens downwards.
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Test Intervals:
- Interval 1: x ≤ -2: Let's test x = -3: -(-3)² + 2(-3) + 8 = -1 ≤ 0. This interval is part of the solution.
- Interval 2: -2 ≤ x ≤ 4: Let's test x = 0: -(0)² + 2(0) + 8 = 8 ≤ 0 (False). This interval is NOT part of the solution.
- Interval 3: x ≥ 4: Let's test x = 5: -(5)² + 2(5) + 8 = -7 ≤ 0. This interval is part of the solution.
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Solution Set: The solution set is (-∞, -2] ∪ [4, ∞). Note the use of brackets [ ] because the inequality includes the roots.
Example 3: 2x² + 5x + 2 ≥ 0
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Standard Form: Already in standard form.
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Find the Roots: Factoring gives (2x + 1)(x + 2) = 0. The roots are x = -1/2 and x = -2.
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Sketch the Parabola: Since a = 2 > 0, the parabola opens upwards.
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Test Intervals:
- Interval 1: x ≤ -2: Test x = -3: 2(-3)² + 5(-3) + 2 = 5 ≥ 0. This interval is part of the solution.
- Interval 2: -2 ≤ x ≤ -1/2: Test x = -1: 2(-1)² + 5(-1) + 2 = -1 ≥ 0 (False). This interval is NOT part of the solution.
- Interval 3: x ≥ -1/2: Test x = 0: 2(0)² + 5(0) + 2 = 2 ≥ 0. This interval is part of the solution.
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Solution Set: The solution set is (-∞, -2] ∪ [-1/2, ∞).
Handling Cases with No Real Roots
If the discriminant (b² - 4ac) of the quadratic equation is negative, the parabola does not intersect the x-axis. In this case, the inequality will either be true for all real numbers or false for all real numbers, depending on whether the parabola opens upwards or downwards and the direction of the inequality.
Example 4: x² + x + 1 > 0
The discriminant is 1² - 4(1)(1) = -3 < 0. The parabola opens upwards (a = 1 > 0). Since it doesn't intersect the x-axis and opens upwards, the inequality is true for all real numbers. The solution set is (-∞, ∞).
Example 5: -x² - x - 1 < 0
The discriminant is (-1)² - 4(-1)(-1) = -3 < 0. The parabola opens downwards (a = -1 < 0). Since it doesn't intersect the x-axis and opens downwards, the inequality is true for all real numbers. The solution set is (-∞, ∞).
Advanced Techniques and Considerations
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Using the Quadratic Formula: When factoring is difficult or impossible, the quadratic formula, x = (-b ± √(b² - 4ac)) / 2a, provides the roots.
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Graphical Methods: Graphing the quadratic function can provide a visual representation of the solution set. The solution set corresponds to the x-values where the graph satisfies the inequality.
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Inequalities with Multiple Factors: For inequalities with multiple factors, a similar process is used. Find the roots of each factor, test the intervals, and combine the results.
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Complex Numbers: While this guide focuses on real number solutions, quadratic inequalities can also have complex number solutions. However, these are typically not considered in introductory algebra courses.
Conclusion
Solving quadratic inequalities is a fundamental skill in algebra. By systematically following the steps outlined above – rewriting in standard form, finding the roots, sketching the parabola, testing intervals, and expressing the solution set – you can confidently tackle a wide range of quadratic inequalities. Remember to pay close attention to the direction of the inequality and whether the roots are included or excluded in the solution set. With practice, you’ll develop fluency and efficiency in solving these types of problems. Understanding the underlying principles and practicing different examples will solidify your understanding and improve your problem-solving abilities significantly.
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